Question

Pls help me solving this

Answer 1

(x+y+z)=9

Squaring both the sides,

(x+y+z)²=(9)²

x²+y²+z²+2(xy+yz+zx)=81

xy+yz+zx= 23(given)

x²+y²+z²+2(23)=81

x²+y²+z²+46=81

x²+y²+z²=81-46

x²+y²+z²= 35

Now,

x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)


Now put all the value on Formula,

x³+y³+z³-3xyz=(x+y+z){x²+y²+z²-(xy+yz+zx)}

x³+y³+z³-3xyz=(9){35-(23)}

x³+y³+z³-3xyz=(9)(35-23)

x³+y³+z³-3xyz=9x12

x³+y³+z³-3xyz= 108


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