Question

pls help me ... thank you ​

Answer 1

P.T     4 (sin⁴30°+cos⁴60°) - 3 (cos²45°-sin²90°) = 2

LHS  = 4(sin⁴30°+cos⁴60°) - 3 (cos²45°-sin²90°)

        = 4 ($(\frac{1}{2} )^{4}$+$(\frac{1}{2} )^{4}$) -3($(\frac{1}{\sqrt{2} } )^{2}$ - 1²)

        = 4 ($\frac{1}{16} }$+$\frac{1}{16} }$)-3($\frac{1}{2} }$-1)

        = 4($\frac{2}{16} }$)-3(-$\frac{1}{2} }$)

        = $\frac{2}{4} }$+$\frac{3}{2} }$

        = $\frac{1}{2} }$+$\frac{3}{2} }$

        = 4/2

        = 2

        = RHS

=> LHS = RHS

Hence Proved