Question

pls help me to do this ​

Answer 1

Explanation:

i. LN=42CM

MQ=15 CM , OP=21CM

area of quadrilateral

[tex] = \frac{1}{2} \times b(h1 + h2) \\ = \frac{1}{2} \times 42(15 + 21) \\ = 21 \times 36 \\ = 756cm²

RJ =24CM

AI=7.5CM

HT=12CM

Area of quadrilateral

={1}{2} × b( h1 + h2 )

= {1}{2} ×24(7.5 + 12)

= 12×19.5

= 234cm²