Question

pls help me to do this sum........pls I need ...pls help me​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$p = 2 + \frac{1}{p} \\ = > p - \frac{1}{p} = 2 \\ = > {(p - \frac{1}{p} )}^{2} = {2}^{2} \\ = > {p}^{2} + \frac{1}{ {p}^{2} } - 2 = 4 \\ = > {p}^{2} + \frac{1}{ {p}^{2} } = 6 \\ = > {({p}^{2} + \frac{1}{ {p}^{2} } )}^{2} = {6}^{2} \\ = > {p}^{4} + \frac{1}{ {p}^{4} } + 2 = 36 \\ = > {p}^{4} + \frac{1}{ {p}^{4} } = 34$

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