,,pls. help me to find
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Given f(x) = x^4 + 2x^3 + 8x^2 + 12x + 18
Given g(x) = 3x^2 + 4x + 1.
Now, Divide f(x) by g(x)
x^2/3 + 2x/9 + 61/27
------------------------------------------------------
3x^2 + 4x + 1) x^4 + 2x^3 + 8x^2 + 12x + 18
x^4 + 4x^3/3 + x^2/3
----------------------------------------------------------------
2x^3/3 + 23x^2/3 + 12x
2x^3/3 + 8x^2/9 + 2x/9
----------------------------------------------------------------------
61x^2/3 + 106x/9 + 18
61x^2/3 + 244x/27 + 61/27
-----------------------------------------------------------------------
74x/27 + 425/27.
Quotient = (x^2/3) + (2x/9) + (61/27)
The remainder is in the form of (74/27)x + (425/27).
Therefore a = 74/27, b = 425/27.
Hope this helps!
Given g(x) = 3x^2 + 4x + 1.
Now, Divide f(x) by g(x)
x^2/3 + 2x/9 + 61/27
------------------------------------------------------
3x^2 + 4x + 1) x^4 + 2x^3 + 8x^2 + 12x + 18
x^4 + 4x^3/3 + x^2/3
----------------------------------------------------------------
2x^3/3 + 23x^2/3 + 12x
2x^3/3 + 8x^2/9 + 2x/9
----------------------------------------------------------------------
61x^2/3 + 106x/9 + 18
61x^2/3 + 244x/27 + 61/27
-----------------------------------------------------------------------
74x/27 + 425/27.
Quotient = (x^2/3) + (2x/9) + (61/27)
The remainder is in the form of (74/27)x + (425/27).
Therefore a = 74/27, b = 425/27.
Hope this helps!
siddhartharao77:
:-)
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