Question

pls help me to find out these both answers which is been marked

Answer 1

Answer:

Solution:

Given

Principal (p) = Rs50000

Rate of interest (r) = 8% p.a

Let the amount at the end of the second year = A

\boxed{Amount = p\times(1+\frac{r}{100})^{n}}

Amount=p×(1+

100

r

)

n

i)

Let the number of times interest paid in 2 years ( n)=2

A = 50000[1+8/100]²

= 50000 × (108/100)²

= 5×108×108

= Rs58320

Therefore,

The amount standing to her

credit at the end of the second

year (A) = Rs58320

ii ) Finding interest for third year:

P = Rs 58320,

R = 8%

T = 1 year

Simple Interest (I) = (PTR)/100

= ( 58320 × 1 × 8 )/100

= Rs 4665.60

••••

Answer 2

Step-by-step explanation:

this is of which class pls dont delete the ans