Question

Pls help me to solve sum no 6 with a diagram from the attachment given below

Answer 1

Answer:

in tri< bec and tri<bdc

be=dc (1/2ab=1/2ac)

bc=bc(common)

<bec=<dec(90°)

so they are congruent by r-h-s

by cpct

<ecb =<dcb (proved)

hope this helps u......

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