Math, asked by ShiriMin, 1 year ago

Pls help me to solve this..
i will mark as brainliest

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Answered by siddhartharao77
4

Step-by-step explanation:

Given Equation is x² + x - (a + 2)(a + 1) = 0

⇒ x² - ax - x + ax + 2x - (a + 2)(a + 1) = 0

⇒ x² - (a + 1)x + (a + 2)x - (a + 2)(a + 1) = 0

⇒ x{x - (a + 1)} + (a + 2){x - (a + 1)}= 0

⇒ {x - (a + 1)}{x + (a + 2)} = 0

x = a + 1 (or) x = -(a + 2)

Hope it helps!


siddhartharao77: :-)
Answered by niral
0

Answer:

Step-by-step explanation:

→ x² + x - (a + 2)(a + 1) = 0

→  x² - ax - x + ax + 2x - (a + 2)(a + 1) = 0

→  x² - (a + 1)x + (a + 2)x - (a + 2)(a + 1) = 0

→  x{x - (a + 1)} + (a + 2){x - (a + 1)}= 0

→  {x - (a + 1)}{x + (a + 2)} = 0

→  x = a + 1 (or) x = -(a + 2)

mark me as brainliest please


niral: mark me as brainliest answer
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