pls help me to solve this my exam is coming near.
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refer to the pic attached
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answer...............
area of square ABCD =1/2 into product of diagonals(as square is also rhombis)
now 1/2×5root2×5root2
=25cm²
now area of square(ABCD) is equal to area (parallelogram DEFC) because they are between same base and same parallels.
hencearea (DEFC)=25cm²
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