Question

Pls help me to solve this question

Answer 1

Answer:

(X+2) is not the factor of this equation

Step-by-step explanation:

1) 2x²+6x+4

=2x²+2x+4x+4

=2x(X+1)+4(X+1)

=(2x+4)(X+1)

Answer 2

Step-by-step explanation:

$1.) \: x + 2 = 0 \\ \boxed{x = - 2} \\ 2 {x}^{2} + 6x + 4 \\ = 2 {( - 2)}^{2} + 6( - 2) + 4 \\ = 8 - 12 + 4 = > 0\\ \blue{ \rightarrow \: (x + 2) \: is \: factor \: of \: 2 {x}^{2} + 6x + 4} \\ 2.) \: x + 2 = 0 \\ \boxed{x = - 2} \\ {x}^{3} + 3 {x}^{2} + 5x + 6 \\ = {( - 2)}^{3} + 3 {( - 2)}^{2} + 5( - 2) + 6 \\ = - 8 + 12 - 10 + 6 \\ = 0 \\ \blue{ \rightarrow \: (x + 2) \: is \: factor \: of \: {x}^{3} + 3 {x}^{2} + 5x + 6} \\ 3.) \: x - 1 = 0 \\ \boxed{x = 1} \\ 4 {x}^{3} + 3 {x}^{2} - 4x + k = 0 \\ 4 {(1)}^{3} + 3 {(1)}^{2} - 4(1) + k = 0 \\ 4 + 3 - 4 + k = 0 \\ \boxed{k = - 3} \\ 4.) \: 6 {x}^{2} + 17x + 5 \\ = 6 {x}^{2} + 15x + 2x + 5 \\ = 3x(2x + 5) + 1(2x + 5) \\ = (3x + 1)(2x + 5) \\ x = - \frac{1}{3} \: \: , \: \: - \frac{2}{5} \\ 5.) \: {y}^{2} - 5y + 6 \\ = {y}^{2} - 3y - 2 y + 6 \\ = y(y - 3) - 2(y - 3) \\ = (y - 2)(y - 3) \\ y = 2 \: \: , \: \: 3 \\ 6.) \: {x}^{3} - 23 {x}^{2} + 142x - 120 \\ = {x}^{2} (x - 23) + 2(71x - 60) \\ 7.) \: x - 2 = 0 \\ \boxed{x = 2} \\ {x}^{3} - 2 {x}^{2} - 2x + 4 \\ = {2}^{3} - 2 {(2)}^{2} - 2(2) + 4 \\ = 8 - 8 - 4 + 4 \\ = 0 \\ \blue{hence \: (x - 2) \: is \: factor \: of \: {x}^{3} - 2 {x}^{2} - 2x + 4} \\ 8.) \: x - a = 0 \\ \boxed{x = a} \\ {x}^{5} - {a}^{2} {x}^{3} + 3x + a - 4 \\ = > {a}^{5} - {a}^{2} {a}^{3} + 3a + a - 4 = 0 \\ = > 4a - 4 = 0 \\ = > \boxed{a = 1} \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$