Question

pls help me with this ;-;​

Answer 1

Answer:

i) The AB part of the graph shows the accelerated motion.

ii) The CD part of the graph shows the retarded motion.

iii) We can measure the distance(s) traveled by this body by the equation =

s = ut + 1/2 at²

Here, u = primary velocity, t = time, a = acceleration

u = 0m/s, t = 4 second, a = 1m/s²

=> s = (0×4) + 1/2×1×4²

=> s = 0 + 8

=> s = 8m

The body traveled 8m in the first 4 seconds.

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