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Given, vertices of quadrilateral : A(−3,5),B(−2,−7),C(1,−8)andD(6,3)
Area of quadrilateral = Area of △ABC + Area of △DAC
Area of triangle = 21(x1(y2−y3)+x2(y3−y1)+x3(y1−y2))
Area of △ABC = 21∣(−3(−7+8)−2(−8−5)+1(5+7))∣
= 21∣(−3+26+12)∣
= 235
Area of △ADC = 21∣(−3(3+8)+6(−8−5)+1(5−3))∣
= 21∣(−33−78+2)∣
= 2109
Area of quadrilateral = 235+2109
Step-by-step explanation:
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