pls help me with this one....
Attachments:
Answers
Answered by
1
If D(AB) is distance of AB, then
AB = √(tanx -0)^2 + (0-1)^2
= √tan^2x + 1
=√sec^2x
= secx
AB = √(tanx -0)^2 + (0-1)^2
= √tan^2x + 1
=√sec^2x
= secx
Similar questions