Math, asked by Anonymous, 1 year ago

Pls help me with this problem urgent pls......l

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Answered by tejas20056

simple intrest = amount - principal
11800-10000=1800
rate =
$\frac{i \times 10}{p \times t?}$
$\frac{1800 \times 100}{10000 \times 2}$
=9%

Anonymous: Dude pls help Rajan borrowed Rs 5000 at 8% p.a. for 3 years.Find the difference between compound interest and simple interest,assuming annual compounding.

tejas20056: so as we find simle interst by fomula p×r×t÷100

tejas20056: find the simple intrest

tejas20056: wich is 1200 and substract it by its compund intrest wich is 1298.56

tejas20056: 1298.56 -1200= 98.56

tejas20056: hre is your answer rupees 98.56

tejas20056: hope you understand

Anonymous: at what rate % of ci will 4000 amount of 5324 in three years? Pls help...sorry for the inconvenience

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