Question

Pls help me with this ques

Answer 1

Answer:

a = -11

b = 5

Step-by-step explanation:

2x² + xy - 3y² + x + ay - 10 = (2x + 3y + b) (x - y - 2)

=> 2x² + xy - 3y² + x + ay - 10 = 2x² + 3xy + bx - 2xy - 3y² - by - 4x - 6y - 2b

=> 2x² + xy - 3y² + x + ay - 10 = 2x² +(3xy - 2xy) - 3y² + (b - 4)x + (-b-6)y - 2b

=> 2x² + xy - 3y² + x + ay - 10 = 2x² + xy - 3y² + (b - 4)x + (-b-6)y - 2b

Equating the coefficients of x,

1 = b - 4

=> b = 5

Equating coefficients of y,

a = - b - 6

=> a = - 5 - 6 = -11

=> a = -11

Equating constants,

-10 = -2b

=> b = 5

Therefore, a = -11 and b = 5.