pls help me with this question
Attachments:
Answers
Answered by
2
Answer:
ΔABC is a right angled triangle
so by Pythagoras theorem
AC²+CB²=AB²
24²+cb²=26²
576 + CB² = 676
CB*CB =676-576
CB*CB = 100
CB*CB = 10*10
CB=10cm
ΔCBE is also a right angle triangle
again by Pythagoras theorem
CE²+EB²=CB²
CE²+8²=10²
CE²+64=100
CE²=100-64
CE*CE=36
CE*CE=6*6
CE=6cm
. : CE in tge above figure is 6cm
hope the answer will help you
kindly mark me as brainlist
Similar questions