Math, asked by chituskitchenrecipie, 19 days ago

pls help me with this question ​

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Answers

Answered by torreselisha17
1

Answer:

5689/90

Step-by-step explanation:

Answered by MathCracker
12

Question :-

Using the formula of (a + b) (a - b), find  \rm{ \bigg( \frac{3}{2}m +  \frac{2}{3} n \bigg) \bigg( \frac{3}{2}m  -  \frac{2}{3}n \bigg) } \\

Step by step explanation :-

Given expression,

\rm{ \bigg( \frac{3}{2}m +  \frac{2}{3} n \bigg) \bigg( \frac{3}{2}m  -  \frac{2}{3}n \bigg) } \\

Also can be written as,

\rm{ \bigg( \frac{3m}{2} +  \frac{2n}{3}  \bigg) \bigg( \frac{3m}{2}  -  \frac{2n}{3} \bigg) } \\

Using formula,

\rm:\longmapsto{(a + b)(a - b) = a {}^{2} - b {}^{2}  }

By using this formula,

\rm:\longmapsto{\rm{ \bigg( \frac{3m}{2} +  \frac{2n}{3}  \bigg) \bigg( \frac{3m}{2}  -  \frac{2n}{3} \bigg) } =  \bigg( \frac{3m}{2}   \bigg) ^{2} -  \bigg( \frac{2n}{3}   \bigg) ^{2}  } \\  \\ \rm:\longmapsto{\rm{ \bigg( \frac{3m}{2} +  \frac{2n}{3}  \bigg) \bigg( \frac{3m}{2}  -  \frac{2n}{3} \bigg) }   =   \boxed { \rm\frac{9m {}^{2} }{4}  -  \frac{4n {}^{2} }{9} }} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

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