Question

pls help me with this question

Answer 1

can't see send it clearly

Answer 2

$\huge\bold\purple{Solution :\longrightarrow}$
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$\mathsf{Let \: \: the \: \: cost \: \: price \: \: of \: \: be \: \: Rs \: \: 100.}$

$\mathsf{Gain \: \: required = 23.5\%}$

•°• selling price = Rs (100 + 23.5) = Rs 123.5

$\mathsf{Let \: \: the \: \: marked \: \: price \: \: be \: \: Rs \: \: x.}$

$\mathsf{Then, \: \: discount = 5\% \: \: of \: \: Rs \: \: x} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{= Rs \: (x \times \frac{5}{100} )} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathsf{= Rs \: \: \frac{x}{20}}$

•°• selling price = MP - discount

$\mathsf{ = > 123.5 = x - \frac{x}{20}}$

$\mathsf{ = > 123.5 = \frac{20x - x}{20}}$

$\mathsf{ = > 123.5 \times 20 = 19x}$

$\mathsf{ = > x = \frac{123.5 \times 20}{19}}$

$\mathsf{ = > x = 6.5 \times 20}$

$\mathsf{ = > x = 130}$

Hence, the marked price is 30% above the cost price.