pls help me with this question if you can..
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Step-by-step explanation:
a cos³x + b sin³x = sinx.cosx. (given)
a cosx (cos²x)+bsin³x=sinxcosx
bsinx (cos²x)+bsin³x=sinx.cosx (as acos x = bsin x)
bsinx(cos²x+sin²x)=sinx.cosx
bsinx(1)=sinx.cosx
cosx=b (put in given equation)
a cosx= b sin x
ab=b sinx
so sinx=a
so a²+b²=sin²x+cos²x=1
Anonymous:
OK bye good night
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