Question

pls help me with this sum​

Answer 1

Answer:

1 g of ice needs 80 cal to become water at 0 C.

1 g of ice needs 80 cal to become water at 0 C. 1 g of water needs 50 cal to rise to 50 C from 0 C. So total the heat needed is 150×80 + 150×50 = 19500 cal. 1 g of steam will supply 540 c to become water at 100 C.1 g of water at 100 C will supply 50 cal to become water at 50 C. Hence x gram of steam at 100 C will supply 590 cal while cooling to 50 C. Hence 19500 = 590 x. Solving, x = 33.05 gram.