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Qᴜᴇsᴛɪᴏɴ :-
show That, (2x + 7) is a factor of 2x³ + 5x² - 11x - 14. Hence Factorize the given Expression completely using the Factor Theorem. ?
Sᴏʟᴜᴛɪᴏɴ :-
→ f(x) = 2x³ + 5x² - 11x - 14
→ (2x + 7) = 0
→ 2x = (-7)
→ x = (-7)/2
So, By Remainder Theorem the Factor will give Remainder as 0.
f(-7/2) = 2x³ + 5x² - 11x - 14 = 0
→ 2(-7/2)³ + 5(-7/2)² - 11(-7/2) - 14 = 0
→ (-343/4) + 245/4 + (77/2) - 14 = 0
→ (-343/4 - 14) + (245/4) + (154/4) = 0
→ (-399/4) + (245/4) + (154/4) = 0
→ (-399/4) + 399/4 = 0
→ 0 = 0
Hence, we can conclude That, (2x + 7) ie a Factor of given Polynomial.
Now, Factorisation :-
→ 2x³ + 5x² - 11x - 14
→ x²(2x + 7) - x(2x + 7) - 2(2x + 7)
→ (2x + 7)(x² - x - 2)
→ (2x + 7)(x² + x - 2x - 2)
→ (2x + 7)[ x(x + 1) - 2(x + 1) ]
→ (2x + 7)(x - 2)(x + 1) (Ans.)
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