Question

pls help meeeeeee...​

Answer 1

Answer:

in rhombus all sides are equal

given that, diagonals are equal

hence, diagonals are perpendicular to each other

please mark as brainliest please follow

Answer 2

sure!

given: rhombus abcd where AO=OC and BO=OD

prove: AC is perpendicular to BD

proof:

since abcd is a rhombus,

ab=bc=cd=da

now considering triangle AOB and triangle COB,

OA=OC (diagonal of a parallelogram bisect each other)

OB=OB (common)

AB=CB (sides of rhombus are equal)

therefore, triangle AOB is congruent to triangle COB by SSS congruency

<AOB=<COB (CPCT) ---------> (1)

since AC is a line,

<AOB+<COB=180° (linear pair)

<AOB+<AOB=180° (From (1))

2<AOB=180°

<AOB=90°

from (1)

<COB =<AOB=90°

so,

<DOC=<AOB=90° (vertically opp angles)

<AOD=<COB=90° (")

since <DOC=<AOB=<AOD=<COB=90°

AC is perpendicular to BD

HENCE PROVED!