Question

pls help n don't spam​

Answer 1

Given,

Total no. Of shirts, n (T) =125

Total no. Of good shirts n(G) =110

Total no. Of minor defect shirt, n(mD) =12

Total no. Of major defect shirt, n(MD) =3

(i)ram lal will buy good shirts

$p_{1} = \frac{no.of \: good \: shirts}{no.of \: total \: shirts} = \frac{n(g)}{n(t)} = \frac{110}{125} = \frac{22}{25}$

(ii) no. Of shirts naveen buys

=n(N) =n(G) +n(mD)

=110+12

n(N) =122

Hence

$p _{2} = \frac{no.of \: shirts \: naveen \: buys}{total \: no.of \: shirts \: } = \frac{n(n)}{n(t)} = \frac{122}{125}$

Answer 2

As it is given in the question

Given,

The Total no. Of shirts, n (T) =125

The Total no. Of good shirts n(G) =110

The Total no. Of minor defect shirt, n(mD) =12

The Total no. Of major defect shirt, n(MD) =3

(i)ram lal will buy good shirts

=

no.oftotalshirts

no.ofgoodshirts

=

n(t)

n(g)

=

125

110

=

25

22

(ii) no. Of shirts naveen buys

=n(N) =n(G) +n(mD)

=110+12

n(N) =122

Hence

=

totalno.ofshirts

no.ofshirtsnaveenbuys

=

n(t)

n(n)

=

125

122.