Math, asked by hshshs6831, 1 year ago

pls help pls pls pls​

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Answered by Grimmjow
12

We know that :

{\bigstar\;\;\boxed{\mathsf{SinA + SinB = 2.Sin\bigg(\dfrac{A + B}{2}\bigg).Cos\bigg(\dfrac{A - B}{2}\bigg)}}}

{\bigstar\;\;\boxed{\mathsf{CosA + CosB = 2.Cos\bigg(\dfrac{A + B}{2}\bigg).Cos\bigg(\dfrac{A - B}{2}\bigg)}}}

\mathsf{Given :\;\;\dfrac{Sin3x + Sinx}{Cos3x + Cosx}}

\mathsf{\implies \dfrac{2.Sin\bigg(\dfrac{3x + x}{2}\bigg).Cos\bigg(\dfrac{3x - x}{2}\bigg)}{2.Cos\bigg(\dfrac{3x + x}{2}\bigg).Cos\bigg(\dfrac{3x - x}{2}\bigg)}}

\mathsf{\implies \dfrac{Sin\bigg(\dfrac{3x + x}{2}\bigg)}{Cos\bigg(\dfrac{3x + x}{2}\bigg)}}

\mathsf{\implies \dfrac{Sin\bigg(\dfrac{4x}{2}\bigg)}{Cos\bigg(\dfrac{4x}{2}\bigg)}}

\mathsf{\implies \dfrac{Sin(2x)}{Cos(2x)}}

\bigstar\;\;\textsf{We know that : \boxed{\mathsf{\dfrac{Sin\theta}{Cos\theta} = Tan\theta}}}

\mathsf{\implies Tan(2x)}


Anonymous: Nice!!
Grimmjow: Thank you! ^_^
hshshs6831: thanks
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