Math, asked by LIKHITHDHARMANA, 7 months ago

pls help pls pls pls pls pls​

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Answered by shweta3539
6

Answer:

2b^2 + 3bc + (-b^2 - bc -c^2 ) + bc + 2c^2

= (2-1)b^2 + (3-1+1) bc + ( -1+2)c^2

= b^2 +3bc +c^2

(b^2 + 3bc +c^2) - (3b^2-c^2 +4 a^2b -8ab^2)

= b^2-3b^2 +3bc +c^2 + c^2 -4a^2b + 8ab^2

= -2b^2 + 2 c^2 +3bc -4a^2b +8ab^2

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