Math, asked by devansh6560, 1 year ago

pls help ques 12 please help fast

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Answered by Anonymous

$let \: principal \: be \: p \\ compound \: interest = p \times {(1 + \frac{r}{100} )}^{2} - p$

$compound \: interest = \frac{729p}{625} - p \\ = \frac{104p}{625}$

$simple \: interest = \frac{ptr}{100} \\ = \frac{16p}{100} \\ = \frac{4p}{25}$

ATQ,
compound interest-simple interest=112

$\frac{104p}{625} - \frac{4p}{25} = 112 \\ = > \frac{4p}{625} = 112 \\ = > p = \frac{112 \times 625}{4}$
principal=17500

devansh6560: isme ci ke formul a pura solve kyu nai kiya

Anonymous: i figured you could do that yourself so i just straightaway wrote the answer

Anonymous: if you want i can do that

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