Pls help quick dear . If you do I will mark you as Brainliest .Pls explain with theory too
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Heya Mate
Here is your answer
###############
In question 14
angle CAB =30 DEGREE
angle ACB=90 DEGREE (angle made in a semicircle)
therefore by ASP of triangle
we can say that,
30+90+x=180
x=180-120
x=60 Degree
In question 15
angle(BOC + AOB)=60+30
=90 DEGREE
we know that,
angle subtended by an arc is double of the angle subtended on the another arc
This implies angle ADC =45 DEGREE
###############
hope it will help u.
Here is your answer
###############
In question 14
angle CAB =30 DEGREE
angle ACB=90 DEGREE (angle made in a semicircle)
therefore by ASP of triangle
we can say that,
30+90+x=180
x=180-120
x=60 Degree
In question 15
angle(BOC + AOB)=60+30
=90 DEGREE
we know that,
angle subtended by an arc is double of the angle subtended on the another arc
This implies angle ADC =45 DEGREE
###############
hope it will help u.
PrinceJK786:
its so low level
Answered by
0
we hey ..hm. dv hjnm jn
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