Question

pls help really needed​

Answer 1

x sin^3 theta + y cos^3 theta = sin theta cos theta

x sin theta. Sin^2 theta + y cos theta. Cos^2 theta = sin theta cos theta

y cos theta. Sin^2 theta + y cos theta. Cos^2 theta = sin theta cos theta

y cos theta ( sin ^2 theta + cos ^2 theta ) = sin theta cos theta

y cos theta = sin theta cos theta

y = sin theta --> ( i )

Since, x sin theta = y cos theta

x sin theta = ( sin theta) ( cos theta )

x = cos theta --> ( ii ).

Squaring both sides in Eqn I and ii,

x^2 + y^2 = sin^2 theta + cos ^2 theta

x^2 + y^2 = 1

Hence, Proved.