Question

pls help
sorry, there are some pen markings, ignore them.
I don't think anyone could solve it​

Answer 1

Answer:

angle BPQ = 115°

Step-by-step explanation:

In triangle ABC,

angle A + angle B + angle C = 180°

( Angle sum property of a triangle)

→ 50° + angle B + 65° = 180°

→ angle B = 180° - 115°

→ angle ABC = 65°

Since BC || PQ

angle APQ = angle ABC (Corresponding angles)

→ angle APQ = 65°

angle APQ + angle QPB = 180° (Linear pair)

→ 65° + angle QPB = 180°

→ angle QPB = 180° - 65°

→ angle QPB = 115°