Question

pls help. (step by step)​

Answer 1

Answer:

Given:

ABCD is a square of side 7cm.

A, B, C & D are the centres of four equal circles each touching two other, externally.

To find:

The area of the entire figure.

Solution:

AB,BC,CD & AD are the distances between the respective centres.

Since ABCD is a square, all angles are right angles and

AB=BC=CD=AD=7cm.

Now the distance between the centres of two circles touching externally, is the sum of their radii.

Here, the radii of the equal circles=

2

1

Side of the given square =

2

7

cm=3.5cm.

Each circle has been cropped by a sector of central angle =90

o

.

∴ A(Cropped cirle) = A(circle) − A(sector)

=π(3.5)

2

cm

2

−

360

0

90

o

×π(3.5)

2

cm

2

∴ A(4 equal circles) =4π×{

4

3

×(3.5)

2

}cm

2

=

7

22

×{3×(3.5)

2

}cm

2

Also, A(square) =7×7cm

2

=49cm

2

.

So, Area of the entire figure= A(4 equal circles)+A(square)

=(115.5+49)cm

2

=164.5cm

2

HOPE THIS HELPS YOU.......

Answer 2

Answer:

Hope this helps u