Question

pls help
step by step working please​

Answer 1

Answer:

hope it's helpful

Step-by-step explanation:

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Answer 2

$\huge\mathcal{{\fcolorbox{lime}{lime}{{\color{black}{Answer~~~↓}}}}}$

$\small{ }$

$\large\bold{To~find~:}$

The value of ‛x’ in the equation :

$\large\mathtt{~~~~{\frac{5x-3}{2}}-{\frac{3x-2}{3}}={\frac{2}{3}}}$

$\large\mathtt{→{\frac{[3(5x-3)]-[2(3x-2)]}{6}}={\frac{2}{3}}}$

$\large\mathtt{→{\frac{(15x-9)-(6x-4)}{6}}={\frac{2}{3}}}$

$\large\mathtt{→{\frac{15x-9-6x+4}{6}}={\frac{2}{3}}}$

$\large\mathtt{→{\frac{9x-5}{6}}={\frac{2}{3}}}$

By cross multiplication, we get :

$\large\mathtt{→3(9x-5)=6×2}$

$\large\mathtt{→27x-15=12}$

$\large\mathtt{→27x=12+15}$

$\large\mathtt{→27x=27}$

$\large\mathtt{→x={\frac{27}{27}}}$

$\large\mathtt{→x={\underline{\underline{1}}}}$

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$\huge\mathrm\color{lime}{Hope~it~helps..!!}$