PLS HELP THE QUESTION IS IN AN IMAGE
Attachments:
Answers
Answered by
4
Answer:
Since 2x = 3y = 4z, we see that: k = 2x, k = 3y, and k = 4z, for some k. Solving these for x, y, and z yields: x = k/2, y = k/3, and z = k/4.03-Apr-2018
Answered by
3
Answer:
hii
good afternoon dear brother.
have a great day ahead.
i don't know answer but
thanks my answer and mark a
pdaksh133 as brilliant.
Similar questions
Accountancy,
1 month ago
Math,
2 months ago
Math,
2 months ago
Math,
9 months ago
Chemistry,
9 months ago