pls help trignometric identities
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Step-by-step explanation:
sin^6A+cos^6A
=(sin²A)³+(cos²A)³
=(sin²A+cos²A)(sin⁴A-sin²Acos²A+cos⁴A)
=(sin⁴A+cos⁴A-sin²Acos²A)
={sin²A+cos²A}² -2sin²Acos²A-sin²Acos²A
=1-3sin²Acos²A
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