Math, asked by Gurneel, 10 months ago

pls help trignometric identities ​

Attachments:

Answers

Answered by sandy1816
2

Step-by-step explanation:

sin^6A+cos^6A

=(sin²A)³+(cos²A)³

=(sin²A+cos²A)(sin⁴A-sin²Acos²A+cos⁴A)

=(sin⁴A+cos⁴A-sin²Acos²A)

={sin²A+cos²A}² -2sin²Acos²A-sin²Acos²A

=1-3sin²Acos²A

Similar questions