Question

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What is the surface area of the cylinder?


If the radius of the cylinder is 6 inches and the height is 9 inches.

Answer 1

Answer

A=2πrh+2πr2=2·π·6·9+2·π·62

≈565.48668in²

Answer 2

Answer:

A=2πrh+2πr2 is the surface area of cylinder formula

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a. Surface area not including bases = 2 π r h = 2 π (6) (9) = 339.3 in2

a. Surface area not including bases = 2 π r h = 2 π (6) (9) = 339.3 in2Surface area including bases = 2 π r h + 2 π r2 = 339.3 + 2 π (6)2 = 565.5 in2

a. Surface area not including bases = 2 π r h = 2 π (6) (9) = 339.3 in2Surface area including bases = 2 π r h + 2 π r2 = 339.3 + 2 π (6)2 = 565.5 in2b. Volume = Area x height = π r2 x h = π (6)2 x 9 = 1,017.9 in3

a. Surface area not including bases = 2 π r h = 2 π (6) (9) = 339.3 in2Surface area including bases = 2 π r h + 2 π r2 = 339.3 + 2 π (6)2 = 565.5 in2b. Volume = Area x height = π r2 x h = π (6)2 x 9 = 1,017.9 in3c. New Volume = Old Volume x 33 = 27.482.7 in3 because each dimension is 3 times larger.

Step-by-step explanation:

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