Question

Pls help with above question.



//1,25//----- this is nothing, just a reference for me. Pls don't mind this.

Answer 1

$\color {red}\huge\bold\star\underline\mathcal{Question:-}$ We have to find sum of digits of n..

$\huge\underline\blue{\sf Given:}$ = x, y and (10x+y) are prime numbers .. and n is largest prime .

$\bold{\boxed{\huge{\boxed{\orange{\small{\boxed{\huge{\red{\bold{\:Answer}}}}}}}}}}$

$since \: n \: is \: largest \: prime \: number \\ \\ x \: and \: y \: also \: will \: be \: largest \: prime$

$x \: is \: a \: single \: digit \: prime </em><em>\</em><em>:</em><em>number</em><em> \: \\ \\so \: x = 2,3,5,7$

$y \: is \: single \: prime \: which \: is \: at \: \\ the \: place \: of \: unit \: \\ \\ so \: y = 3 \: , \: 7 \: \\ <u>(if \: we \: take \: 2 \: or \: 5 \: \\ then \: it \: won't \: be \: a \: prime \: number.)$

$all \: possible \: values \: of \: (10x+y) = \\ 23,27,33,37,53,57,73,77$

Now,

$When \: we \: look \: at \:(10x+y) \\ n \: term \: can \: be \: largest \: if \: x=7 \: and \: y=3$

So ,

A/q,

$n \: = \: x \times y \times (10x+y) \\ </p><p></p><p>n=7 \times 3 \times (70+3) \\ </p><p></p><p>n=21 \times 73 \\ n</p><p></p><p>=1533</p><p></p><p> \: \\ so \: sum \: of \: digits \: of \: n \\ =(1+5+3+3)=12$

$\large\red{\boxed{\sf 12\:is\:Your\:Ans.}}$

$\huge\blue{THANKS}$

Answer 2

Answer:

x and y = largest prime.

x = single digit prime number.

x = 2 , 3 , 5 , 7

y = single digit prime.

y = 3 , 7

= ( 10x + y )

= 23,27,33,37,53,57,73,77

• 10x + y
• x = 7
• y = 3

n = x × y ( 10x + y )

n = 7 × 3 × ( 70 + 3 )

n = 21 × 73

n = 1533

= ( 1 + 5 + 3 + 3 ) = 12