Question

Pls help with above question.

Answer 1

Answer:

h=44.1/9.8

=3.5

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Answer 2

$\huge\pink{\underline{\pink{\underline{\green{\bigstar{\blue{\mathbb{ANSWER}}}}}}}}$

Let the total time be t

Distance travelled in t-1 sec is

$\blue{=44.1m}\\Using\: S=ut+\frac{1}{2}at{}^{2}\\since\: the\: stone\: is \:dropped\\ hence\: intial\: \:velocity \:=\:0\\S=0(t-1)+\frac{1}{2}9.8(t-1){}^{2}\\44.1={1}{2}9.8(t-1){}^{2}\\\frac{44.1\times2}{9.8}=(t-1){}^{2}$

$\frac{88.2}{9.8}=(t-1){}^{2}\\</p><p>0.09=(t-1){}^{2}$

$(t - 1) = \sqrt{0.09} \\ t - 1 = 0.3 \\ \red{t = 1.3sec}$

Hence total time for journey is 1.3 sec

Using

$S=ut+\frac{1}{2}at{}^{2}\\H=0(1.3)+\frac{9.8\times(1.3){}^{2}}{2}\\H=\frac{16.562}{2}\\\bold\green{H=8.21m}$