Question

Pls help with method​

Answer 1

Answer:

2³/3⁶

Step-by-step explanation:

let the unknown number be x

$( - 2 \div 3) {}^{ - 3} \div x = ( - 4 \div 27) {}^{ - 3} \\ x = ( - 2 \div 3) {}^{ - 3} \div ( - 4 \div 27) {}^{ - 3} \\ || as \: a {}^{c} \div b {}^{c} = (a \div b) {}^{c} || \\ = > x = | ( - 2 \div 3) \div ( - 4 \div 27)| {}^{ - 3} \\ x = |( - 2 \div 3) \times ( - 27 \div 4) | {}^{ - 3} \\ x = (9 \div 2) {}^{ - 3} \\ x = (2 \div 9) {}^{3} \\ x = 2 {}^{3 } \div 9 {}^{3} \\ x = 2 {}^{3} \div (3 {}^{2}) {}^{3 } \\ x = 2 {}^{3} \div 3 {}^{6}$

From above written solution you can understand better.

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