pls
help with my math's homework
Question ;
If n(A) = 300, n(AUB) = 500, n(AB) = 50 and n(B') = 350, find n(B) and n(U).
give correct answer
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Answers
Answered by
4
Answer:
n(aub)=n(a)+n(b)-n(anb)
500=300+n(b)-50
500-250=n(b)
250=n(b)
n(u)=n(b')+n(b)
n(u)=350+250=600
Yes I was also wondering that
...n is actually a sign used for intersection of sets ...now this is correct answer ..
hope it helped
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