Chemistry, asked by suhas122006, 5 months ago

pls help (with step by step)​

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Answered by Anonymous
27

\sf K.E = \dfrac{3}{2}RT \\ \\

\sf K.E\:is\:directly\:proportional\:to\:T \\ \\

\sf 20°C \longrightarrow\\ \\ \sf 40°C \\ \\

\sf Using\:formula, \\ \\

\sf K.E = \dfrac{3}{2}RT \\ \\

\sf \frac{K_{40}}{K_{20}} = \frac{T_{40}}{T_{20}} \\ \\

\sf =\dfrac{273+40}{273+20}\\ \\

\sf =\dfrac{313}{293}\\ \\

\sf Hence,\:option\:2\:is\:correct.

Answered by Samhita347
3

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