Question

Pls help with the thirteenth question

Answer 1

Answer:

The values of x is 3 and 12.

Step-by-step explanation:

According to question:-

Dividend = $(x+1)^{2}$

Divisor = (x - 2)

Quotient = 16

Reminder = (x - 3)

x =?

We know that-

Dividend = Quotient × Divisor + Remainder

$(x+1)^{2} = 16(x-2) + (x-3)$

$x^{2} + 1+ 2x = 16x - 32 + x - 3$

$x^{2} +2x+1 = 17x - 35$

$x^{2} + 2x + 1 -17x + 35 = 0$

$x^{2} - 15x + 36 = 0$

$x^{2} -(12+3)x +36= 0$

$x^{2} -12x - 3x + 36 = 0$

$x(x-12) -3(x-12) = 0$

$(x-3)(x-12) = 0$

If (x - 3) = 0

Then x = 3

If (x - 12) = 0

Then x = 12

Hence, the values of x is 3 and 12.

Answer 2

Answer:

A tough question worked very hard to answer this.

I think it will help.