pls help with this math
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Step-by-step explanation:
B°=ACB°= x [angles of an isosceles triangle]
AB=AD [ Given]
but,
AB=AC
=> AD=AC
=> ACD°=D°= y [ angles of isosceles triangle]
In triangle BCD
= B + C + D = 180° [ Angle Sum Property]
=> x + (x+y) + y =180° {C°= ACD°+ACB°= x+y}
2(x+y) = 180
x+y=90°
HENCE, BCD IS A RIGHT ANGLED TRIANGLE
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