Question

pls hlp me
Will mark u as brainliest​

Answer 1

it's your ans-

Option D is correct

It is present in 4th period. So, move to 4th period in periodic table.

Now, given that it has 5 electrons in outer most shell so it will definately in 15th group.

If it has 5 electrons in outermost so 3 will be unpaired because 8 electrons is present in octet state.

Element will be Arsenic.

I hope you understand...