Question

pls hlp q14 and q15

Answer 1

hope this will help you ...

Answer 2

Answer:

Step-by-step explanation:

Q15.)  let speed of the streamer be x

upstream= x-1  

downstream = x+1

now,

3*t1 = t2

3*D/S = D/S

3* 30/4+x = 30/ 4-x

cancelling 30 on both sides

3/4+x = 1/4-x

3(4-x) = 4+x

12-3x = 4+x

12-4 = x+3x

8 = 4x

8/4 = x

2 = x

therefore, x =  2 km/hr

Q14. )   2x²+x-6

⇒2x²+4x-3x-6

⇒2x(x+2)-3(x+2)

⇒(2x-3)(x+2)

⇒x=3/2 and x=-2

let alpha = 3/2 and beta = -2

so 2 alpha and 2 beta is ⇒ 2×3/2=3= 2 alpha and 2 beta = -4

so now 2 alpha+ 2 beta = 3+(-4)=-1

and 2 alpha × 2 beta = 3×(-4)= -12

so are quadratic equation will be x² -( sum of zeroes)x + (product of zeroes)

⇒x²-(-1)x+(-12)

⇒x²+x-12