Question

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Answer 1

Answer:

CEB + CED = 180

130+CED = 180

CED =180-130

CED = 50

CED+EDC+DCE=180

50+20+CDE = 180

CDE = 180-70

CDE = 110

CDB = BAC

BAC = 110

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Answer 2

Answer:

Step-by-step explanation:

Here, ∠BEC+∠DEC=180∘   (Linear pairs are complimentary)  

⟹ 130∘  

+∠DEC=180 ∘  

⟹ ∠DEC=50 ∘    

In ΔDEC,  

∠DEC+∠ECD+∠CDE=180∘    (Angle sum property)  

⟹ 50 ∘ +20 ∘  

+∠CDE=180  ∘  

⟹ ∠CDE=110  ∘  

By theorem of circles,  

∠BAC=∠CDB  

⟹ ∠BAC=∠CDE=110  o

∴∠BAC=110 ∘

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