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If cos A=3/5 and sin B=7/25,where A is acute and B is obtuse , find without using tables ,the values of cos (A+B)
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first triangle 3,4, 5 in quad 1
second triangle 24, 7 , 25 in quad II
now look at it
with triangle similar to A in quadrant III but 8 tiems lengths
x = - 24, same as triangle A
y = -32
hypotenuse = 40
so
I have a triangle in Quadrant III with hypotenuse 40 and leg 24 along -x axis
what is angle below -y axis ?
cos T = -24/40 = -3/5
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