Question

Pls I need this answer

Answer 1

Const : Join OA , OB , OM , OD, draw a ⊥ on CD from O.

Proof : In ΔOMA and ΔOBM, By using Pythagoras theorem we get,

(OM)²+(AM)² = (OA)²      ,      (OM)²+(MB)² = (OB)²    

∴ Now substituting the values of radius in these eqn we get,

(AM)² = 25-9                  ,       (MB)² = 25-9

⇒ AM = 4                       ,       MB = 4

Now as Chord AB = AM+MB

∴ AB= 8 cm

  ii)  I don't know