Question

pls I want the answer really fast​

Answer 1

Explanation:

AB = 9 m

BC = 40 m

i) Let the length of AC be x

the ∆ABC is a right angled triangle.

So,

AC is the hypotenuse of triangle

AC² = AB² + BC²

AC² = 9² + 40²

AC =√1681

AC = 41 m

ii)

Let two semicircles in the figure be one full circle.

radius r = 9/2 = 4.5 m

circumference= 2 π r

= 2 × 3.14 × 4.5

= 28.26 m

perimeter of the given figure= 28.26 + 2 × 40

= 28.26 + 80

= 108.26m

cost of fencing per metre = 2 rupees

cost of fencing 108.26 metres = 108.26 × 2

= 216.52 rupees

iii)

area of the shaded portion :

Let two semicircles in the figure be one full circle.

area of the circle = π r²

= 3.14 × 4.5 × 4.5

= 3.14 × 20.25

= 63.545 m²

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