Question

pls its urgent rd sharma class 9​

Answer 1

Step-by-step explanation:

$f(x) = {9x}^{3} - {3x}^{2} + x - 5 \\ g(x) = x - \frac{2}{3}$

$zeros \: of \: g(x) = g(x) = 0 \\ x - \frac{2}{3 } = 0 \\ x = 0 + \frac{2}{3} \\ x = \frac{2}{3}$

$remainder = >$

$p(x) = {9x}^{3} + {3x}^{2} + x - 5$

Remaining explanation see in attachment

Answer 2

Answer:

f(x)=9x

3

−3x

2

+x−5

g(x)=x−

3

2

\begin{gathered}zeros \: of \: g(x) = g(x) = 0 \\ x - \frac{2}{3 } = 0 \\ x = 0 + \frac{2}{3} \\ x = \frac{2}{3} \end{gathered}

zerosofg(x)=g(x)=0

x−

3

2

=0

x=0+

3

2

x=

3

2

\begin{gathered}remainder = > \\ \end{gathered}

remainder=>

p(x) = {9x}^{3} + {3x}^{2} + x - 5p(x)=9x

3

+3x

2

+x−5

Step-by-step explanation:

Hope it helps!