Pls let me know the answer of both this question ... pls make it possible with the required solution!
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Answered by
1
Answer:
∠ACB + ∠ADB = 180°
Step-by-step explanation:
From figure:
⇒ ∠CAB = ∠CDA
⇒ ∠CBA = ∠CDB
In ΔACB,
⇒ ∠ACB + ∠CAB + ∠CBA = 180° {Sum of angles = 180°}
⇒ ∠ACB + (∠CDA + ∠CDB) = 180°
⇒ ∠ACB + ∠ADB = 180°
Hope it helps!
Answered by
0
∠ACB + ∠ADB = 180°
Step-by-step explanation:
From figure:
⇒ ∠CAB = ∠CDA
⇒ ∠CBA = ∠CDB
In ΔACB,
⇒ ∠ACB + ∠CAB + ∠CBA = 180° {Sum of angles = 180°}
⇒ ∠ACB + (∠CDA + ∠CDB) = 180°
⇒ ∠ACB + ∠ADB = 180°
@skb
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