Question

pls look at the image and answer the qns​

Answer 1

Answer:

$\huge{\mathcal{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}$

Given:

PQ⊥PR,∠RQT=38⁰ and ∠QTL=75⁰

To find: x and y

Now:

We can write, ∠RTQ+∠QTL=180⁰ (Linear Pair)

=>∠RTQ+75⁰=180⁰

=>∠RTQ=105⁰--------(i)

Since, PQ||RL

Therefore, we can write:

∠RTQ+∠PQT=180⁰ (Sum of co-interior ∠s=180⁰)

=>105⁰+(∠PQR+∠RQT)=180⁰ (∠PQT can be written as ∠PQR+∠RQT)

=>105⁰+y+38⁰=180⁰ (∠PQR=y and ∠RQT=38⁰)

=>y=(180-143)

=>y=37⁰ or ∠PQR=37⁰

In ∆PQR,

∠PQR+∠QRP+QPR=180⁰(Angle sum property of ∆)

=>37⁰+x+90⁰=180⁰

=>x=53⁰

Hope it helps you buddy ❤️